2500 gold
5 pirates

Set the initial 2 pirates gold equal as follows:
x = total gold

100 + [(x-100)/6] = 200 + [(x - 200 - 100 - ((x-100)/6)/6]

Rearranging and solving:
x - 100 = 300 + x - [(x-100)/6]

And again:
0 = 400 - [(x-100)/6]

And again:
0 = 2400 - x + 100

Therefore x = 2500

Substitue this value into the equation for Pirate 1

On Thu, Mar 3, 2011 at 1:32 PM, Lavesh Rawat <lavesh.ra...@gmail.com> wrote:

> *Split the Booty Problem Solution*
> *
> *
> A pirate crew at the end of the day split the booty. The first pirate got
> 100 gold pieces, and 1/6 of the remaining booty. The second one got 200 gold
> pieces, and 1/6 of the remaining booty. The third one got 300 gold pieces,
> and 1/6 of the remaining booty. Ect. The last one only got, what if left
> from the booty.
> At the end, every pirate had the same ammount of gold pieces (from the
> booty).
> How many pirates were there, and how much was the booty.
>
> Update Your Answers at : Click 
> Here<http://dailybrainteaser.blogspot.com/2011/03/3march.html>
>
> Solution:
> Will be updated after 1 day
>
>
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