in order to deal with such situations u have to read the input till the end
of file
if your algo is correct then using EOF something like
while(scanf("%d",&n)!=EOF) will give u AC..!!

On Sun, Mar 13, 2011 at 2:01 PM, Logic King <crazy.logic.k...@gmail.com>wrote:

> I tried the problem https://www.spoj.pl/problems/NHAY/
>
> I didn't Understand the Input of the problem --
> The length of the needle is only limited by the memory available to your
> program, so do not make any assumptions - instead, read the length and
> allocate memory as needed. The haystack is *not* limited in size, which
> implies that your program should not read the whole haystack at once. The
> KMP algorithm is stream-based, i.e. it processes the haystack character by
> character, so this is not a problem.
>
> my code works fine i the size of both the strings are limited
>
> i created my own algo...didn't did it by KMP.....plz help me how to control
> the large input !!
>
>
> my code is--
>
> #include<stdio.h>
> #include<string.h>
>
> int main()
> {
>     int t,i,j,n,l1,l2;
>     char p[10000000],str[10000000];
>     scanf("%d",&t);
>     while(t--)
>     {
>         scanf("%d",&n);
>         i=0;
>         scanf("%s",p);
>         scanf("%s",str);
>         l1=strlen(str);l2=strlen(p);
>         for(j=0;j<l2;)
>         {
>
>                 if(i<l1)
>                 {
>                     if(str[i]==p[j])
>                     {
>                         if(j==l2-1)
>                         {
>                         printf("%d\n",i-l2+1);
>                         j=0;
>                         i=i-l2+2;
>                         }
>                         else
>                         {
>                         i++;
>                         j++;
>                         }
>                     }
>                     else
>                     {
>                         if(j==0)
>                             i++;
>                         else
>                             j=0;
>                     }
>                 }
>                 else
>                     break;
>         }
>         printf("\n");
>     }
> return 0;
> }
>
>
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