@dave...plz read the q carefully before answering the q.....
nice link anurag...:))

On Sun, Mar 20, 2011 at 11:03 PM, Dave <dave_and_da...@juno.com> wrote:

> @Akash: The sum of the numbers from 1 to n is S(n) = n*(n+1)/2. Thus,
> the sum of the numbers from a to b is S = S(b) - S(a-1) = ( b*(b+1) -
> a*(a-1) ) / 2.
>
> Dave
>
> On Mar 20, 9:08 am, Akash Mukherjee <akash...@gmail.com> wrote:
> > Majid is a 3rd-grade elementary student and quite well in mathematics.
> Once,
> > Majid's teacher asked him to calculate the sum of numbers 1 through n.
> >
> > Majid quickly answered, and his teacher made him another challenge. He
> asked
> > Majid to calculate the sum of the digits of numbers 1 through n.
> >
> > Majid did finally find the solution. Now it is your turn, can you find a
> > solution?
> > Input
> >
> > Two space-separated integers 0 <= a <= b <= 109.
> >
> > Program terminates if a and b are -1.
> > Output
> >
> > The sum of the digits of numbers a through b.
> > Example
> >
> > *Input:*
> > 1 10
> > 100 777
> > -1 -1
> > *Output:*
> > 46
> > 8655
> >
> > ne ideas??
>
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-- 
Sanchit Mittal
Second Year Undergraduate
Computer Engineering
Delhi College of Engineering
ph- +919582414494

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