wouldn't a modified dijkstra do the trick??

On 4/2/11, Tech id <ilovea...@gmail.com> wrote:
> Given a directed graph G, with V vertices and E edges. Each edge in E
> is associated with a real number ‘r’,a reliabilty factor with r
> between 0(exclusive) and 1(inclusive). You are also given a pair of
> nodes u and v. Find the most reliable path in the given graph from u
> to v.
> Input will be the graph represented as a matrix with the following
> format:
> * the number of vertices n. (therefore, A is an nxn matrix)
> * The elements of A, row-wise: (total n*n numbers)
> A(i,j) = 0 denotes that the edge (i,j) is not present
> A(i,j) between 0 (exclusive) and 1 (inclusive) indicates
> that the edge (i,j) is present with reliability A(i,j).
> Output: Your output will be a sequence of vertices giving the path
> from u to v such as 1,4,3,5,8,6,7 with u=1 and v=7. The output is thus
> a comma separated list of vertices giving the path from u to v.
>
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