@Dave: This is what is still a doubt to me. I have searched but couldn't get
the info regarding this.
On Fri, May 20, 2011 at 8:01 AM, Dave <dave_and_da...@juno.com> wrote:
> @Aakash: And tell me how map works. Is making an entry O(1) regardless
> of the value of the entry? For example, is it O(n) to map the sequence
> 1, 4, 9, 16, 25, ..., n^2?
>
> Dave
>
> On May 20, 9:39 am, Aakash Johari <aakashj....@gmail.com> wrote:
> > @Dave: I got you. I will have to check before pushing the element in map.
> >
> >
> >
> >
> >
> > On Fri, May 20, 2011 at 7:30 AM, Dave <dave_and_da...@juno.com> wrote:
> > > @Aakash: Yeah, but try the same array with sum = 6 and see what
> > > happens.
> >
> > > Dave
> >
> > > On May 20, 9:04 am, Aakash Johari <aakashj....@gmail.com> wrote:
> > > > int main()
> > > > {
> > > > int a[10] = {5, 3, 10, 9, 8, 23, 11, 4, 12, 6};
> > > > int i;
> > > > int sum;
> > > > int flag = 0;
> >
> > > > map<int, int> m;
> >
> > > > for ( i = 0; i < 10; i++ ) {
> > > > m[a[i]] = 1;
> > > > }
> >
> > > > sum = 13;
> >
> > > > for ( i = 0; i < 10; i++ ) {
> > > > if ( m[sum - a[i]] == 1 ) {
> > > > flag = 1;
> > > > break;
> > > > }
> > > > }
> >
> > > > if ( flag == 1 )
> > > > cout << a[i] << " " << sum - a[i] << endl;
> >
> > > > return 0;
> >
> > > > }
> > > > On Fri, May 20, 2011 at 7:01 AM, hari <rajakin...@gmail.com> wrote:
> > > > > We can sort using STL sort function in main() before function call
> of
> > > > > arraysum().
> >
> > > > > On May 20, 6:49 am, Gunjan Sharma <gunjan.khan...@gmail.com>
> wrote:
> > > > > > First of all there is an infinite loop in this code....
> > > > > > Secondly it works only for sorted array.
> >
> > > > > > On Fri, May 20, 2011 at 7:16 PM, hari <rajakin...@gmail.com>
> wrote:
> > > > > > > In while loop have i,j which points first and last index of
> array.
> > > In
> > > > > > > while loop, Check the sum of a[i],a[j], If sum<k,increment i or
> > > else
> > > > > > > decrement j. Run the while loop till i<j..
> >
> > > > > > > CODE:
> >
> > > > > > > int arraysum(int a[], int k, int i, int j)
> > > > > > > while(i<j)
> > > > > > > {
> > > > > > > int p=0;
> > > > > > > int b[10]; //to store index of selected nos
> > > > > > > sum=a[i]+a[j];
> > > > > > > if (sum==k)
> > > > > > > {
> > > > > > > b[p++]=i;b[p++]=j;
> > > > > > > }
> > > > > > > elseif(sum<k)
> > > > > > > i++;
> > > > > > > else(sum>k)
> > > > > > > j++;
> > > > > > > return b;
> > > > > > > }
> >
> > > > > > > On May 20, 4:38 am, amit <amitthecoo...@gmail.com> wrote:
> > > > > > > > given an array of integers, and an integer k, find out two
> > > elements
> > > > > > > > from the array whose sum is k in O(n) time. if no such
> element
> > > exists
> > > > > > > > output none.
> >
> > > > > > > --
> > > > > > > You received this message because you are subscribed to the
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> > > > > > --
> > > > > > Regards
> > > > > > Gunjan Sharma
> > > > > > B.Tech IV year CSE
> >
> > > > > > Contact No- +91 9997767077
> >
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> >
> > > > --
> > > > -Aakash Johari
> > > > (IIIT Allahabad)- Hide quoted text -
> >
> > > > - Show quoted text -
> >
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> > --
> > -Aakash Johari
> > (IIIT Allahabad)- Hide quoted text -
> >
> > - Show quoted text -
>
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--
-Aakash Johari
(IIIT Allahabad)
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