read ch1 in understanding pointers in c by kanetkar.. it says tht if u use
%d format specifier to print a float an unknown value will come.. and if use
%f to print an integer then also unknown value will come.. so u r not
supposed to switch format specifiers like this
On Sun, Jun 5, 2011 at 12:33 AM, Rohit Sindhu <
rohit.sindhu.spec...@gmail.com> wrote:
> Your format specifiers in the printf statements are not right.
> Also integers and floats are stored differently internally. Also, you have
> to explicitly cast float into int as automatic conversion is not applicable
> here in printf.
>
> I hope this code helps your cause ,
>
> #include<stdio.h>
>
> int main()
> {
> float a[]={13.24,1.5,1.5,5.4,3.5};
> float *j;
> j=a;
> j=j+4;
> printf("\n%p,%f,%f",j,*j,a[4]);
>
> float p=3.5;
> printf("\n%f,%d",p,(int)p);
>
> p=4.5;
> printf("\n%d,%f",(int)p,p);
>
>
> }
>
>
>
>
>
>
> On Sat, Jun 4, 2011 at 2:21 PM, himanshi narang <
> himanshinarang...@gmail.com> wrote:
>
>> #include<stdio.h>
>>
>> int main()
>> {
>> float a[]={13.24,1.5,1.5,5.4,3.5};
>> float *j;
>> j=a;
>> j=j+4;
>> printf("\n%d,%d,%d",j,*j,a[4]);
>>
>> float p=3.5;
>> printf("\n%f,%d",p,p);
>>
>> p=4.5;
>> printf("\n%d,%f",p,p);
>>
>> }
>>
>>
>> output----
>> -1080027596,0,1074528256
>> 3.500000,0
>> 0,0.000000
>>
>> plzz explain y i m getting dis output......
>>
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>
>
>
> --
> Rohit Sindhu
>
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