it will definitely give wrong results...

try for -3 -2 -1 0 1 2 4 5 7

and search for 6 using ur algo

On 6/7/11, Shivaji Varma <shivaji...@gmail.com> wrote:
> How about this?
>
> Take two pointers, one pointing to the first element in the array and second
> one pointing to second element in the array. If the difference is less than
> 'k', increment the second pointer and if the difference is greater,
> increment the first pointer. And if pointer 1 exceeds pointer 2, then the
> search pair (a,b) doesn't exist.
>
> On Tue, Jun 7, 2011 at 3:20 PM, ross <jagadish1...@gmail.com> wrote:
>
>> @piyush:
>> in the case of a+b=k,
>> assuming a and b are 2 ptrs to start and end,
>> when u increase a, sum increases and when u decrease b
>> sum decreases. i doubt if that s the same case for a-b..
>>
>> On Jun 7, 2:47 pm, ross <jagadish1...@gmail.com> wrote:
>> > Can u use the same logic u use for a+b=k for difference..
>> > because, here if you increase a or decrease b in both case
>> > difference will increase.. ? correct me if i am wrong.
>> >
>> > On Jun 7, 2:39 pm, Piyush Sinha <ecstasy.piy...@gmail.com> wrote:
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > > Whats the problem in using two pointers one pointing the lower index
>> while
>> > > the other pointing the upper index??
>> >
>> > > On Tue, Jun 7, 2011 at 2:57 PM, ross <jagadish1...@gmail.com> wrote:
>> > > > Given an integer 'k' and an sorted array A (can consist of both
>> > > > +ve/-
>> > > > ve nos),
>> > > > output 2 integers from A such that a-b=k.
>> > > > PS:
>> > > > nlogn solution would be to check for the occurence of k-a[i] (using
>> > > > bin search) when you
>> > > > encounter a[i]. methods like hash consume space.
>> >
>> > > > Is an O(n) solution with O(1) extraspace possible?
>> >
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>> > > --
>> > > *Piyush Sinha*
>> > > *IIIT, Allahabad*
>> > > *+91-8792136657*
>> > > *+91-7483122727*
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-- 
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