we can take care of the duplicate entries, but then that would cost more
space(int), as of now we are working with bool

On Mon, Jun 13, 2011 at 5:51 PM, sunny agrawal <sunny816.i...@gmail.com>wrote:

> that will report duplicate entries multiple times :(
>
>
> On Mon, Jun 13, 2011 at 5:38 PM, sunny agrawal <sunny816.i...@gmail.com>wrote:
>
>> why do we need 2 bits at all ??
>> i think single bit per table entry will do.
>> say table is T[1025], and array is A[M]
>>
>>
>> 1. Go through the N sized array and set bit 0 of the hash table entry to 1
>> if it is present in the first array.
>> 2. Go through the M sized array and if T[a[i]] is set then this element is
>> there in second array else not.
>>
>> any cases this can fails??
>>
>> On Mon, Jun 13, 2011 at 5:28 PM, Divye Kapoor <divyekap...@gmail.com>wrote:
>>
>>> Use a hash table of size 1025 with bits per table entry = 2.
>>> 1. Go through the N sized array and set bit 0 of the hash table entry to
>>> 1 if it is present in the first array.
>>> 2. Go through the M sized array and set bit 1 of the hash table entry to
>>> 1 if the element belongs to 0 to 1024.
>>> 3. Go through the hash table and print entries with bit values 11.
>>>
>>> Space usage = O(1), 2050 bits (rounded off to the corresponding nearest
>>> byte). Time complexity = O(N + M)
>>>
>>> --
>>> DK
>>>
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>>
>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
>>
>
>
> --
> Sunny Aggrawal
> B-Tech IV year,CSI
> Indian Institute Of Technology,Roorkee
>
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-- 
Regards,
Arpit Sood

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