i still din't get the solution..please explain..

On 6/16/11, LALIT SHARMA <lks.ru...@gmail.com> wrote:
> ++*p++
> ==>
> ++(*p++) ,
> increments the value stored at p , and also increments p .
>
>
>
> On Thu, Jun 16, 2011 at 1:10 PM, sunny agrawal
> <sunny816.i...@gmail.com>wrote:
>
>> The place where strict constness is not enforced is with character
>> array literals. You can say
>> char* cp = "howdy";
>> and the compiler will accept it without complaint. This is
>> technically an error because a character array literal (“howdy” in
>> this case) is created by the compiler as a constant character array,
>> and the result of the quoted character array is its starting address in
>> memory. Modifying any of the characters in the array is a runtime
>> error, although not all compilers enforce this correctly.
>> So character array literals are actually constant character arrays. Of
>> course, the compiler lets you get away with treating them as nonconst
>> because there’s so much existing C code that relies on this.
>> However, if you try to change the values in a character array literal,
>> the behavior is undefined, although it will probably work on many
>> machines.
>> If you want to be able to modify the string, put it in an array:
>> char cp[] = "howdy";
>> Since compilers often don’t enforce the difference you won’t be
>> reminded to use this latter form and so the point becomes rather
>> subtle.
>>
>>
>> On Thu, Jun 16, 2011 at 12:59 PM, amit kumar
>> <amitthecoo...@gmail.com>wrote:
>>
>>> //kk
>>> //In place of
>>>
>>> char *p="hai friends",*p1;
>>> if i declare as
>>> char p[]="hai friends";
>>> char *p1;
>>> //then ??
>>>
>>>
>>> On Thu, Jun 16, 2011 at 8:16 AM, DIPANKAR DUTTA <
>>> dutta.dipanka...@gmail.com> wrote:
>>>
>>>> It's ok..
>>>>
>>>> char *p="hai friends"...not correct....
>>>>
>>>> bcz you did allocate memory for that string but assiging poiter to the
>>>> base address.. from where gcc will get the bse address of that string
>>>> when u
>>>> r not actually allocate memory for it? thus it generate SIGSEG signal
>>>> and
>>>> give invalid memory address...ie. segmentation fault
>>>> use malloc or use
>>>> char p[]="..";
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>> On Thu, Jun 16, 2011 at 4:49 AM, DK <divyekap...@gmail.com> wrote:
>>>>
>>>>> Gives me a SEGFAULT on gcc.
>>>>> Probably due to undefined behaviour.
>>>>>
>>>>> --
>>>>> DK
>>>>>
>>>>> http://twitter.com/divyekapoor
>>>>> http://www.divye.in
>>>>>
>>>>> --
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>>>>
>>>>
>>>>
>>>> --
>>>> Thanks and Regards,
>>>> ------------------------------
>>>> *DIPANKAR DUTTA*
>>>> Visiting Research Scholar
>>>> Dept of Computing,
>>>> Macquarie University, Sydney, Australia
>>>> ph.no-+61 2 98509079 ( Mon-Fri 10:15-7:00) Sydney time
>>>> email: dipankar.du...@mq.edu.au
>>>>
>>>>
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>>>
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>>
>>
>>
>> --
>> Sunny Aggrawal
>> B-Tech IV year,CSI
>> Indian Institute Of Technology,Roorkee
>>
>>
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>
>
>
> --
> Lalit Kishore Sharma,
>
> IIIT Allahabad (Amethi Capmus),
> 6th Sem.
>
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-- 
Regards,
Kamakshi
kamakshi...@gmail.com

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