Vaibhav,

We are not finding two numbers with sum "X". Here we are talking about
subset. :)

@Navneet
Please see this link
http://www-ti.informatik.uni-tuebingen.de/~reinhard/krypto/English/4.5.1.e.html

PS: You might have seen it before. In that case ignore it.

~
Oppilas

On Mon, Jun 20, 2011 at 12:21 PM, vaibhav shukla <vaibhav200...@gmail.com>wrote:

> sort the array using merge sort : order nlogn
> take the first element,subtract it with 'k' , then search the result using
> binary search in rest of the array : order nlogn
> hence u get two elements which sum up to K in order nlogn
>
>
> On Mon, Jun 20, 2011 at 12:14 PM, Navneet Gupta <navneetn...@gmail.com>wrote:
>
>> Right, in the worst case, complexity with be O(2^N).
>>
>> So what are the possible optimizations here? Would building pre-computed
>> data structures with intermediate sum values help in finding such pairs in
>> less complexity? I think then we can apply dynamic programming to find such
>> pairs.
>>
>>
>> On Mon, Jun 20, 2011 at 12:09 PM, oppilas . <jatka.oppimi...@gmail.com>wrote:
>>
>>> I think its a NP problem. The solution complexity can go up O(2^N) in
>>> worst case.
>>>
>>> On Mon, Jun 20, 2011 at 11:55 AM, Navneet Gupta 
>>> <navneetn...@gmail.com>wrote:
>>>
>>>> Given a set of integers , find a set of numbers such that they sum to a
>>>> given number k .
>>>> Notice the set of numbers can have 2 or more than 2 numbers.
>>>>
>>>>
>>>> --Navneet
>>>>
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>>
>>
>>
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>> --Navneet
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>
>
>
> --
>   best wishes!!
> Vaibhav Shukla
>     DU-MCA
>
>
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