@oppilas
thanks!


Wladimir Araujo Tavares
*Federal University of CearĂ¡

*




On Tue, Jun 21, 2011 at 9:47 PM, oppilas . <jatka.oppimi...@gmail.com>wrote:

> @Wladmir.
> If you see carefully,then it is quite obvious that product of n
> consecutive number will be divisible by n!.
>
> 3 must be a divisor of at least one number out of three consecutive
> number.( because each multiple of 3 lies, 3 number ahead of previous
> one.)
> Similarly, we can argue for ith number. that it will be a divisor of
> at least one number out of i consecutive number.
>
> On 6/22/11, Wladimir Tavares <wladimir...@gmail.com> wrote:
> > @sunny agrawal
> > In theory, it would be necessary to prove that the product of n
> consecutive
> > numbers is divisible by n!
> > do you agree?
> >
> >
> > Wladimir Araujo Tavares
> > *Federal University of CearĂ¡
> >
> > *
> >
> >
> >
> >
> > On Tue, Jun 21, 2011 at 5:01 PM, kartik sachan
> > <kartik.sac...@gmail.com>wrote:
> >
> >> sir i think the same ans i gave the above..........
> >>
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