I was reading in somewhere the ternary operator is *right associative*
Wladimir Araujo Tavares
*Federal University of Ceará
*
On Fri, Jun 24, 2011 at 1:13 AM, Vishal Thanki <vishaltha...@gmail.com>wrote:
> Okay, I found the problem i think,
>
> (x > 10) ? y++: x = 10 is evaluated as ((x > 10) ? y++: x) = 10
> which is wrong..
>
> (x > 10) ? y++: (x = 10) will work.
>
>
> On Fri, Jun 24, 2011 at 9:22 AM, Vishal Thanki <vishaltha...@gmail.com>
> wrote:
> > yes, i understand that.. but is there any limitation in ternary
> > operator that the 2nd expression (after ":")should not use assignment
> > operator?
> >
> >
> >
> > On Fri, Jun 24, 2011 at 9:21 AM, Wladimir Tavares <wladimir...@gmail.com>
> wrote:
> >> Try this:
> >> #include <stdio.h>
> >> #include <stdlib.h>
> >> int main(int argc, char *argv[])
> >> {
> >> int x = atoi(argv[1]);
> >> int y = 10;
> >> x = (x > 10) ? y++: 10;
> >> return x;
> >> }
> >> Wladimir Araujo Tavares
> >> Federal University of Ceará
> >>
> >>
> >>
> >>
> >>
> >>
> >> On Fri, Jun 24, 2011 at 12:40 AM, Vishal Thanki <vishaltha...@gmail.com
> >
> >> wrote:
> >>>
> >>> Hey all,
> >>>
> >>> I think I am missing something very basic in C, and which is troubling
> >>> me. Following code is not compiling for me, can anyone explain why?
> >>>
> >>> vishal@ubuntu:~/progs/c\ 09:07:01 AM >$ cat ternary.c
> >>> #include <stdio.h>
> >>> #include <stdlib.h>
> >>> int main(int argc, char *argv[])
> >>> {
> >>> int x = atoi(argv[1]);
> >>> int y = 10;
> >>> (x > 10) ? y++: x = 10;
> >>> return x;
> >>> }
> >>> vishal@ubuntu:~/progs/c\ 09:07:08 AM >$ gcc ternary.c
> >>> ternary.c: In function ‘main’:
> >>> ternary.c:7: error: lvalue required as left operand of assignment
> >>>
> >>>
> >>> Vishal
> >>>
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