@Shachindra
If you are using binary tree then why are you doing sorting first?

@ANKIT
Yes  you can't do searching of sum of two numbers in less then O(n*n).

On Tue, Jun 28, 2011 at 6:23 PM, Shachindra A C <sachindr...@gmail.com>wrote:

> @ankit : I'm pretty confident that the second part of your solution cannot
> be done in O(n) time. Correct me if I am wrong!! Nevertheless, the overall
> time complexity remains O(n*log(n)), as you pointed out.
>
>
> On Tue, Jun 28, 2011 at 5:59 PM, Shachindra A C <sachindr...@gmail.com>wrote:
>
>> @Ankit
>> Can you please explain the method to get the answer to the second subpart
>> of your solution in O(n) time?
>>
>> My solution to solve the problem in O(n log(n)) time is as follows:
>>
>> Insert the nodes of the sorted array into a binary tree. Then start with
>> the first node. Subtract the value of the node from X. Then search for the
>> result of the subtraction in the binary tree. This can be done in O(log n)
>> time, giving O(nlogn) for the overall complexity of the second subproblem.
>>
>> Please explain your logic.
>>
>>
>> On Tue, Jun 28, 2011 at 5:48 PM, Nitish Garg <nitishgarg1...@gmail.com>wrote:
>>
>>> Can you please explain how to solve the 2nd question?
>>>
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>>
>>
>> --
>> Regards,
>> Shachindra A C
>>
>>
>
>
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> Regards,
> Shachindra A C
>
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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