A similar solution has been proposed above if I am not misinterpreting the
code,You are creating a bitmap from the 2 variables.?
On Mon, Jul 11, 2011 at 4:55 PM, Anika Jain <anika.jai...@gmail.com> wrote:
>
> A c code for this is:
>
> int main()
> {
> int a[2] = {0};
> char str[50];
> int i,ind=0;
> scanf ("%s", str);
> for(i=0;i<strlen(str);i++)
> {
>
> if(str[i]>='a' && str[i]<='z')
> {
> if(!(a[0] & 1<<str[i]-'a'))
> {
> a[0] = a[0] | 1<<str[i]-'a';
> str[ind]=str[i];
> ind++;
> }
> }
> else if(str[i]>='A' && str[i]<='Z')
> {
> if(!(a[1] & 1<<str[i]-'a'))
> {
> a[1] = a[1] | 1<<str[i]-'a';
> str[ind]=str[i];
> ind++;
> }
> }
> }
> str[ind]='\0';
>
> printf("%s\n",str);
> return 0;
> }
>
>
> is it fine 2 use 2 integers for this? or not allowed??
>
>
>
> On Mon, Jul 11, 2011 at 9:35 AM, Yaw <yawbrob...@gmail.com> wrote:
>
>> Quite new to java what do you think of mine?
>>
>> import java.util.*;
>>
>> public class RemoveDuplicates {
>>
>>
>> public static void main(String[] args){
>> while(true) {
>> System.out.println("Enter String");
>> Scanner input = new Scanner(System.in);
>> String str = input.nextLine();
>> System.out.println(RemoveDup(str));
>> }
>> }
>>
>> public static String RemoveDup(String str){
>> str = str.toLowerCase();
>> String temp = "";
>> for (int i=0; i<str.length(); i++){
>> if (!temp.contains(Character.toString(str.charAt(i)))){
>> temp+=str.charAt(i);
>> }
>>
>> }
>> return temp;
>>
>>
>> }
>>
>> }
>>
>>
>
>
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>
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--
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD
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