@dheeraj: but the prototypes are same..... how u are calling it
overloading plz explain
On 7/12/11, dheeraj tyagi <dheeraj2...@gmail.com> wrote:
> const means that it cannot be overloaded..i think due to that this is
> happening.
>
> On Tue, Jul 12, 2011 at 9:26 PM, segfault <pawan1991ya...@gmail.com> wrote:
>
>> #include<iostream>
>> using namespace std;
>> class x{
>> public:
>> x() {}
>>
>> int func() const{
>> cout<<"it is const function\n";
>> }
>>
>> int func() {
>> cout<<"it is simple functin\n";
>> }
>>
>>
>> };
>> int main()
>> {
>> x a;
>> a.func();
>> return 0;
>> }
>>
>> why cann't it take const function?
>> explain it
>>
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>
>
> --
> With regards
> Dheeraj Tyagi
> 8197218001
>
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