@nicks so many problems could be solved in O(n) but it is very difficult to
find a hashing function where there is no collision...
and if we sort the list, we are modifying the list... which lets assume is
not allowed............. then what to do ?
suppose even if we know the index at which there are duplicates for every
unique number even then the solution will be O(n^2) because you cant jump
directly to that index

On Wed, Jul 13, 2011 at 8:52 PM, nicks <crazy.logic.k...@gmail.com> wrote:

> agree with saurabh.....merge sort will be the best.....using sorting
> problem can be solved in O(nlogn)
> else use hashing to solve in O(n)
>
> @shady.....ya that would be most obvious solution can be done easily in
> O(n^2).
>
> On Wed, Jul 13, 2011 at 8:36 PM, shady <sinv...@gmail.com> wrote:
>
>> what are the constraints ?
>> if none then it could be done easily. O(N^2) solution
>>
>> On Wed, Jul 13, 2011 at 8:10 PM, Anika Jain <anika.jai...@gmail.com>wrote:
>>
>>> how to remove duplicates from a linked list?? is it mandatory to sort the
>>> list first?l
>>>
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