ya guys m sorry actually swap code within the function is working ryt and
swap code wasnt working ryt.. i did misunderstood sumthing..
@sandeep sir: thanku sir :)
On Thu, Jul 14, 2011 at 11:26 AM, Sandeep Jain <sandeep6...@gmail.com>wrote:
> Your swap function is not correct. You are swapping p & q locally. Since
> you are using c++, make the following changes.
> void swap*(node* &p,node* &q)*
> {
> node *t;
> t=p;
> p=q;
> q=t;
> }
>
>
>
> Regards,
> Sandeep Jain
>
>
>
>
> On Thu, Jul 14, 2011 at 1:45 AM, Anika Jain <anika.jai...@gmail.com>wrote:
>
>> n sorry i have wriiten it in c++ not c..
>>
>>
>> On Thu, Jul 14, 2011 at 1:44 AM, Anika Jain <anika.jai...@gmail.com>wrote:
>>
>>> by using swap function is pointer to a pointer used then??
>>>
>>>
>>> On Thu, Jul 14, 2011 at 1:36 AM, Piyush Kapoor <pkjee2...@gmail.com>wrote:
>>>
>>>> u need a pointer to a pointer to swap the pointers...
>>>>
>>>>
>>>> On Thu, Jul 14, 2011 at 1:21 AM, Anika Jain <anika.jai...@gmail.com>wrote:
>>>>
>>>>> can some body tell me that:
>>>>>
>>>>> void swap(node *p,node *q)
>>>>> {
>>>>> node *t;
>>>>> t=p;
>>>>> p=q;
>>>>> q=t;
>>>>> }
>>>>>
>>>>> void mirror(node *p)
>>>>> {
>>>>> if (p==NULL)
>>>>> return;
>>>>>
>>>>> else
>>>>> { mirror(p->r);
>>>>> mirror(p->l);
>>>>> swap(p->r,p->l);
>>>>> }
>>>>> }
>>>>>
>>>>> in this the swapping is occuring but if i do :
>>>>>
>>>>> void mirror(node *p)
>>>>> {
>>>>> if (p==NULL)
>>>>> return;
>>>>>
>>>>> else
>>>>> { mirror(p->r);
>>>>> mirror(p->l);
>>>>> node *t;
>>>>> t=p->r;
>>>>> p->r=p->l;
>>>>> p->l=t;
>>>>> }
>>>>> }
>>>>>
>>>>>
>>>>> here it is not getting done .. why??
>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> *Regards,*
>>>> *Piyush Kapoor,*
>>>> *CSE-IT-BHU*
>>>>
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>>>
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