@Damanshu for
1
/ \
2 3
/ \
4 5
/ \
6 7
im ending up at some non BST
surender
On Tue, Jul 19, 2011 at 4:06 AM, Dumanshu <duman...@gmail.com> wrote:
> @Gaurav: The best solution would be to manipulate the given BTree in
> place and get the BST. We don't need a separate tree but convert the
> existing one using the same space occupied by nodes of BT already in
> BST.
>
> On Jul 19, 2:06 am, Gaurav Popli <gpgaurav.n...@gmail.com> wrote:
> > cant we just do....traverse using recursion and instead of printing it
> > just pass to function which is making BST....??
> > and is this right as someone above said first sort it and then make
> BST...
> > dont we want that root of both Tree to be same or something like
> that...??
> >
> >
> >
> > On Tue, Jul 19, 2011 at 2:17 AM, Dumanshu <duman...@gmail.com> wrote:
> > > @Balaji: for third question, were u asked to write the code?
> >
> > > On Jul 18, 10:04 pm, Balaji S <balaji.ceg...@gmail.com> wrote:
> > >> wats the mistake..
> >
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