i+1 * i+1
= 2 * i + 1
for i = 3, j = 7 (2 *3 + 1)
On Mon, Jul 25, 2011 at 6:06 PM, Arshad Alam <alam3...@gmail.com> wrote:
> what should be the output of the following and how..
>
>
> #include<stdio.h>
> #include<conio.h>
> #define PRODUCT(x) (x*x)
> void main()
> {
> clrscr();
> int i=3,j;
> j=PRODUCT(i+1);
> printf("\n%d",j);
> getch();
> }
>
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