no problem .. but can u find a bug in this technique .. On Fri, Jul 29, 2011 at 8:17 PM, saurabh singh <saurab...@gmail.com> wrote:
> ignore above status...i was looking at two problems > simulataneously...posted on the wrong one... > apologies...really its embarrasing. > > On Fri, Jul 29, 2011 at 8:11 PM, snehi jain <snehijai...@gmail.com> wrote: > >> thanks .. >> @siddhartha : i know the hashing technique ... and the problem of longer >> strings can be reduced by subtracting a large constant value from the ASCII >> value of all the characters .. and its not only with cubes even if u add >> squares of ascii values ... i think it will work . >> >> @saurabh : in what context should i use bitfield ... >> >> >> >> On Fri, Jul 29, 2011 at 7:36 PM, saurabh singh <saurab...@gmail.com>wrote: >> >>> use a bitfield to optimize space >>> >>> >>> On Fri, Jul 29, 2011 at 7:14 PM, Siddharth kumar < >>> siddhartha.baran...@gmail.com> wrote: >>> >>>> #include<iostream> >>>> #include<string.h> >>>> >>>> using namespace std; >>>> >>>> int main() >>>> { >>>> char str1[] = >>>> "sdfgkirertyujvcheddirtyutrdfgrtyuigfkrertyuijhgfdshh"; >>>> char str2[] = >>>> "redirtyhgfdshhrtyrsujvcheierdutrdfgrtyuigfkdfgktyuij"; >>>> int len1 = strlen(str1), len2 = strlen(str2); >>>> >>>> if(len1 != len2) >>>> { >>>> cout<<"Both are not anagram of each other."; >>>> return 0; >>>> } >>>> else >>>> { >>>> int rep_char1[26] = {0}, rep_char2[26] = {0}, i; >>>> >>>> for(i=0; i<len1; i++) >>>> { >>>> rep_char1[str1[i]-'a']++; >>>> rep_char2[str2[i]-'a']++; >>>> } >>>> >>>> for(i=0; i<26; i++) >>>> if(rep_char1[i] != rep_char2[i]) >>>> { >>>> cout<<"Both are not anagram of each other."; >>>> return 0; >>>> } >>>> >>>> cout<<"Both are anagram of each other."; >>>> } >>>> return 0; >>>> } >>>> >>>> >>>> >>>> -- >>>> Siddharth Kumar >>>> BE 4th year, Computer Engineering >>>> (Delhi College of Engineering) >>>> +919711559760 >>>> >>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "Algorithm Geeks" group. >>>> To post to this group, send email to algogeeks@googlegroups.com. >>>> To unsubscribe from this group, send email to >>>> algogeeks+unsubscr...@googlegroups.com. >>>> For more options, visit this group at >>>> http://groups.google.com/group/algogeeks?hl=en. >>>> >>> >>> >>> >>> -- >>> Saurabh Singh >>> B.Tech (Computer Science) >>> MNNIT ALLAHABAD >>> >>> >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Saurabh Singh > B.Tech (Computer Science) > MNNIT ALLAHABAD > > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.