In the statement,
i=i++ + f(i),
i++ is evaluated first. At this point i=0. The i passed to the function f()
has the value 1.
1 is printed in the function. 0 is returned. now the expression
i= i++ + f(i)
becomes
i=0+0
thus the value of i is changed to 0.
On Sat, Aug 6, 2011 at 8:29 PM, swetha rahul <swetharahu...@gmail.com>wrote:
> Hi,
> class C{
> static int f1(int i) {
> System.out.print(i + ",");
> return 0;
> }
> public static void main (String[] args) {
> int i = 0;
> i = i++ + f1(i);
> System.out.print(i);
> }}
>
>
> Why does this print 1,0..?? Please explain...
>
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