got it.. thanks guys

On Mon, Aug 8, 2011 at 8:00 PM, mohit verma <mohit89m...@gmail.com> wrote:

> No .. in this case it  flags error.
>
>
> On Mon, Aug 8, 2011 at 7:58 PM, Dipankar Patro <dip10c...@gmail.com>wrote:
>
>> does the answer still remain same if you do the following:
>>
>> const int d=1;
>>
>> const int *const ptr = &d;
>>
>> In your version I don't see ptr pointing to a const int. It just points to
>> an integer, which I think can be changed.
>> See if the code I suggested still does the same as your version...
>>
>> On 8 August 2011 19:53, mohit verma <mohit89m...@gmail.com> wrote:
>>
>>> In c++
>>>
>>> int d=1;
>>> const int *const ptr = &d;   means ptr is const ptr to const object .So
>>> neither ptr nor d can be changed. But
>>>
>>> when i do -
>>>  d=5;
>>> cout<<d<<" "<<*ptr;
>>> the values are changed. Why is it so?
>>> Moreover doing something like : *ptr=5 gives error. Can someone explain
>>> internals here?
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>>> ........................
>>> *MOHIT VERMA*
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