Int bit3:4 will be read as lower order 4 bits of bit3 and this will be
treated as int (signed). Thus lower order bit of bit3 which is 2, are
0010 which is 2
try with
1) int bit3:2, output will be -2
2) unsigned int bit3:2, output will be 2.
I hope it is cleared now
On 8/9/11, Rohit Srivastava <access2ro...@gmail.com> wrote:
> #include<stdio.h>
> #include<conio.h>
>
> int main()
> {
> struct value
> {
> int bit1:1;
> int bit3:4;
> int bit4:4;
> }bit={1,2,2};
> printf("%d %d %d\n",bit.bit1,bit.bit3,bit.bit4);
> getche();
> return 0;
> }
> the above code gives output : -1 2 2
> any idea why???
>
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