no code... algorithm has been stated, implement it urself

On Mon, Aug 15, 2011 at 12:18 AM, Karthikeyan palani <
karthikeyan...@gmail.com> wrote:

> code pls??
>
>
> On 15 August 2011 00:16, aditya kumar <aditya.kumar130...@gmail.com>wrote:
>
>> it can be done in O(3n). in worst case one row will have max and anothr
>> row will have min so the third row will be your o/p to print
>>
>>
>> On Mon, Aug 15, 2011 at 12:00 AM, Karthikeyan palani <
>> karthikeyan...@gmail.com> wrote:
>>
>>> sorry O(n^2) s the time complexity
>>>
>>>
>>> On 14 August 2011 23:56, shady <sinv...@gmail.com> wrote:
>>>
>>>> how can it be O(n) when there are itself n*n elements..
>>>>
>>>> PS : no sharing of code, else the inevitable
>>>>
>>>> On Sun, Aug 14, 2011 at 11:51 PM, Karthikeyan palani <
>>>> karthikeyan...@gmail.com> wrote:
>>>>
>>>>> Given a n x n matrix. .number are randomly placed. .print any one row
>>>>> which doesn’t have min
>>>>> and max elements. Time Complexity : 0(n)
>>>>>
>>>>>
>>>>>
>>>>> if anyone know the code.. pls share!!!
>>>>>
>>>>> --
>>>>> karthikeyankkn
>>>>>
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