The question is directly taken from coreman...read it,the best is
explained there

On Wed, Aug 17, 2011 at 7:10 PM, Adi Srikanth <adisriika...@gmail.com> wrote:
>
> there is something anamoly about this birthday probability caculation. Search 
> in google..you may find it.
>
>
> Regards,
> Adi Srikanth.
> Mob No 9887233349
> Personal Pages: adisrikanth.co.nr
>
>
> On Wed, Aug 17, 2011 at 6:25 PM, Romil ....... <vamosro...@gmail.com> wrote:
>>
>> Take it as:
>> P(atleast 2) = 1-P(no 2 have same b'day) = 1- ((365C50)/50!)
>> where C represents the combinations
>>
>> On Wed, Aug 17, 2011 at 6:14 PM, sukran dhawan <sukrandha...@gmail.com> 
>> wrote:
>>>
>>> can yo explain it pl?
>>>
>>> On Wed, Aug 17, 2011 at 6:11 PM, Aditya Jain <aditya2...@gmail.com> wrote:
>>>>
>>>> Is that exactly 2 or atleast 2?
>>>>
>>>> P(atleast 2)=1-P(no 2 people )=1-(364*363*362*.........*317/365^49)
>>>>
>>>>
>>>>
>>>>
>>>>
>>>> On Aug 17, 5:24 pm, priya ramesh <love.for.programm...@gmail.com>
>>>> wrote:
>>>> > nothing is specified. I guess it's 365
>>>>
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>>
>>
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>> Romil
>>
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--
Saurabh Singh
B.Tech (Computer Science)
MNNIT ALLAHABAD

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