@ Mehnaaz :the variable no_p will be equal to 0,since it is an
external one
so the declaration char p[no_p][max] is equivalent to p[0][max];
and size of p is zero.
then how you can insert anything into it
as you are doing in for loop?
no_p may receive some non zero value afterwards but array p is not re-
declared so
it doesnt has any space alloted to it ,then how for loop is working
without any glitch?
On Aug 24, 5:58 pm, Mehnaaz <mehnaazmohiud...@gmail.com> wrote:
> #include <stdio.h>
> #define max 30
> int no_p;
> int main() {
>
> char p[no_p][max];
> char x;
> int i=0;
> printf("enter the no of productions..\n");
> scanf("%d", &no_p);
> printf("you have entered :%d\n", no_p);
> printf("Variable who's FOLLOW you want\n");
> scanf("%c", &x);
> printf("you have entered :%c",X);
> printf("\n");
> for( i =0 ; i< no_p ; i++){
> printf("enter the production # %d",i+1);
> scanf("%s",p[i]);
> }
> //follow(p,x);
> return 0;
>
> }
>
> the output i am getting goes like this
> ......................................
> enter the no of productions..
> 3
> you have entered :3
> Variable who's FOLLOW you want
> you have entered :
>
> enter the production # 1
> ...........................................
> at the line 4 of the output its supposed to wait for my scanf() entry
> value right??..but it executes the printf after that giving "you have
> entered"
>
> i'm using gcc to compile this
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