void getSquareRoot(float s)
{
float a=s;
int i=0;
for(i=0;i<20;i++)
{
a=(s+a*a)/(2*a);
}
printf("square root is %f",a);
}
On Tue, Aug 30, 2011 at 6:00 PM, Sanjay Rajpal <srn...@gmail.com> wrote:
> Binary Search kind of mathod is useful here :
>
> float SquareRoot(float n,float start,float end)
> {
> float s=(start+end)/2;
> if(n - sqr(s) < 0.001) && (n - sqr(s) > -0.001))
> return (end+start)/2;
> else if(sqr(s) > n)
> return SquareRoot(n,0.0,s);
> else
> return SquareRoot(n,s,end);
> }
>
> Sanju
> :)
>
>
>
> On Tue, Aug 30, 2011 at 3:25 AM, UTKARSH SRIVASTAV <
> usrivastav...@gmail.com> wrote:
>
>> i don't whethe you have studied a subject cbnst from that use newton
>> raphson method
>>
>>
>> On Tue, Aug 30, 2011 at 2:39 AM, Ankuj Gupta <ankuj2...@gmail.com> wrote:
>>
>>> U can use binary search method
>>>
>>> On Aug 30, 1:56 pm, Rajeev Kumar <rajeevprasa...@gmail.com> wrote:
>>> > use Babylonian method(Efficient) algrithm..............
>>> > Refer :
>>> http://en.wikipedia.org/wiki/Methods_of_computing_square_roots#Babylo...
>>> >
>>> > public *void* getSquareRoot(double s) {
>>> > double Xn = 2.0;
>>> > double lastXn = 0.0;
>>> > while (Xn != lastXn) {
>>> > lastXn = Xn;
>>> > Xn = (Xn + s / Xn) / 2.0;
>>> > }
>>> > return Xn;
>>> > }
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> > On Tue, Aug 30, 2011 at 1:49 PM, Ankur Garg <ankurga...@gmail.com>
>>> wrote:
>>> > > @techcoder
>>> >
>>> > > Making an array of 32768 or INT_MAX will make ur compiler cry
>>> >
>>> > > Also ur case doesnt handle the scenario where square root is a
>>> decimal
>>> > > number
>>> >
>>> > > On Tue, Aug 30, 2011 at 1:35 PM, tech coder <
>>> techcoderonw...@gmail.com>wrote:
>>> >
>>> > >> the sqrt of 32 bit number can't be more than 16 bits.
>>> >
>>> > >> have an array of 2^16 elemnts wtih elemts 1 2 3 4 5 .... 32768 .
>>> >
>>> > >> now apply binary search
>>> > >> i=a[mid] where mid=(lower+upper)/2
>>> >
>>> > >> if(i*i==num)
>>> > >> i is the sqrt
>>> >
>>> > >> increment lower and upper accordingly as we do in binary search
>>> >
>>> > >> so order is Ologn where n=2^16
>>> >
>>> > >> On Tue, Aug 30, 2011 at 11:37 AM, Raghavan <its...@gmail.com>
>>> wrote:
>>> >
>>> > >>> how to design this logic effectively?
>>> >
>>> > >>> double squareRoot(int num){
>>> >
>>> > >>> }
>>> >
>>> > >>> --
>>> > >>> Thanks and Regards,
>>> > >>> Raghavan KL
>>> >
>>> > >>> --
>>> > >>> You received this message because you are subscribed to the Google
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>>> >
>>> > >> --
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>>> >
>>> > > --
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>>> > > "Algorithm Geeks" group.
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>>> >
>>> > --
>>> > Thank You
>>> > Rajeev Kumar
>>>
>>> --
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>>>
>>>
>>
>>
>> --
>> *UTKARSH SRIVASTAV
>> CSE-3
>> B-Tech 3rd Year
>> @MNNIT ALLAHABAD*
>>
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>>
>
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