int main()
{
fork();
fork() && fork() || fork();
fork();
printf("forked\n");
return 0;
}
ln 1 : will create 2 prs
ln 2 : will create 10 process for each existing pr
ln 3 : will do fork for all 10 process, nd so now u ve 20 prs
the main issue is @ln-2 in main( )
Ln 2 :
here for 1st fork, if its parent, its ret value in nonzero, so it will
proceed for next fork, as that is for &&. if ret value of this 2nd fork is
nonzero, it willn't try the 3rd fork (as its nt required, bcoz that comes
after ||, nd the st is already a true st) -- > So for parent of 1st fork in
the st, total no of prs created is 3.
if 1st fork returns 0, ie if it is child, it willn't attempt the next
fork(bcoz thatz for operator && , and the st is already 0), bt it will do
attempt the 3rd fork(bcoz that is for operator ||) so total no processes
created here is - 2
Ln 3- this fork is called for all created processes. 2(Ln 1) * 5(ln 2) * 2
(ln 3) == 20 prs
On Wed, Aug 31, 2011 at 12:29 PM, SANDEEP CHUGH <sandeep.aa...@gmail.com>wrote:
> it will be 16 ..
>
> On Wed, Aug 31, 2011 at 9:54 PM, abhishek <abhishek.ma...@gmail.com>wrote:
>
>>
>> i think it will be 16 (not sure )
>>
>> can anyone explain how it will be 20,
>> On Aug 31, 9:02 pm, SANDEEP CHUGH <sandeep.aa...@gmail.com> wrote:
>> > i thinks it is 16 not 20
>> >
>> > please check that
>> >
>> > On Wed, Aug 31, 2011 at 9:18 PM, annarao kataru <
>> kataruanna...@gmail.com>wrote:
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > > @swathi :: why it is 20 times ?? ur answer is correct but
>> > > plz explain the process??????
>> >
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