foo(char []s){
printf("%d", sizeof(s));
}

even now it prints 4.
My point is s pointer in foo and a is also a constant pointer in main. (a is
passed to foo)
However, in main a is treated as an rvalue and in s the same pointer is an
lvalue. why??

Someone plz reply. It's urgent

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to