@mohit :good one
On Sun, Sep 4, 2011 at 4:34 PM, mohit verma <mohit89m...@gmail.com> wrote:
> hey guys
> why hashing?
> can't we simply sort the array of characters in-place - space complexity
> O(1) .
> and then simply rearrange the array in-place with character+frequency.
>
> On Sun, Sep 4, 2011 at 3:13 PM, bharatkumar bagana <
> bagana.bharatku...@gmail.com> wrote:
>
>> +1 rahul and +1 ankuj
>>
>>
>> On Sat, Sep 3, 2011 at 11:37 AM, icy` <vipe...@gmail.com> wrote:
>>
>>> Just use a hash to count frequency of something; e.g. in ruby:
>>> ar= %w(a a b c a b b c d e a d e f)
>>> freq=Hash.new(0)
>>> ar.each {|c| freq[c]+=1}
>>> p freq
>>>
>>> #output
>>> #{"a"=>4, "b"=>3, "c"=>2, "d"=>2, "e"=>2, "f"=>1}
>>>
>>> you could only do it in place in O(1) only if your input array is
>>> already 2*(number of all possible characters) size, but you didnt
>>> mention size of input array. For example, what if input was just
>>> [a,b,c,d,e] ? The size is 5. You cant just convert the input
>>> into [a,1,b,1,c,1,d,1,e,1] without increasing the size to 10. So
>>> hash is the better method.
>>>
>>> On Sep 3, 11:04 am, Ankuj Gupta <ankuj2...@gmail.com> wrote:
>>> > if for all inputs you array remains of same size we can take it as
>>> > constant space
>>> >
>>> > On Sep 3, 7:49 pm, rajul jain <rajuljain...@gmail.com> wrote:
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> >
>>> > > @ankuj just want to clarify that in hashing method we require array
>>> of
>>> > > fixed size let say arr[26] , so is it considered as constant space or
>>> not?
>>> >
>>> > > On Sat, Sep 3, 2011 at 8:02 PM, siddharam suresh <
>>> siddharam....@gmail.com>wrote:
>>> >
>>> > > > sol already posted please search old thread
>>> > > > Thank you,
>>> > > > Sid.
>>> >
>>> > > > On Sat, Sep 3, 2011 at 8:01 PM, Ankuj Gupta <ankuj2...@gmail.com>
>>> wrote:
>>> >
>>> > > >> If we take our input to be characters a-z ans A-Z then we require
>>> > > >> fixed space which can be treated as O(1).
>>> > > >> On Sep 3, 7:10 pm, teja bala <pawanjalsa.t...@gmail.com> wrote:
>>> > > >> > this 'll work if u i/p the string in dis manner
>>> > > >> > aaabbcc(consecutive same)
>>> > > >> > a3b2c2
>>> >
>>> > > >> > #include<stdio.h>
>>> > > >> > #include<conio.h>
>>> > > >> > main()
>>> > > >> > {
>>> > > >> > int x=1,i=0;
>>> > > >> > char a[100];
>>> > > >> > gets(a);
>>> > > >> > while(a[i]!='\0')
>>> > > >> > {
>>> > > >> > while(a[i]==a[i+1])
>>> > > >> > {
>>> > > >> > x++;
>>> > > >> > i++;
>>> > > >> > }
>>> > > >> > printf("%c%d",a[i],x);
>>> > > >> > x=1;
>>> > > >> > i++;
>>> > > >> > }
>>> > > >> > getchar();
>>> >
>>> > > >> > }
>>> >
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>>
>>
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>>
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>
>
>
> --
> ........................
> *MOHIT VERMA*
>
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