We can use linked HashMap................
Refer :
http://download.oracle.com/javase/6/docs/api/java/util/LinkedHashMap.html
On Mon, Sep 5, 2011 at 1:42 PM, bharatkumar bagana <
bagana.bharatku...@gmail.com> wrote:
> @Anup:
> how can u say that the hash function used is a%10 ....
> That is internal , not in the hands of user ..
> Usually while inserting a value in Hash Table , we don't give the size of
> the table ahead ... It decides some size, and implements.. when we cross the
> assumed size,then it again gives some more memory so that all the operations
> are optimum (less collisions).....
>
>
> On Sun, Sep 4, 2011 at 5:32 PM, Anup Ghatage <ghat...@gmail.com> wrote:
>
>> Sid,
>>
>> I'm afraid a hash table won't help much.
>>
>> Given the elements as follows: { 10,20,30,10,20,20,30,30,30,30,10 }
>>
>> All of them will be hashed into the 0'th cell for a % 10 hash function,
>> and then probably the overflow will be handled by chaining.
>> So that will be governed by m^2 in worst case.
>>
>> So the algorithm would be O( m^2 log m ) just to populate the hash and
>> find the frequencies.
>>
>> --
>> Anup Ghatage
>>
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>
>
>
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Thank You
Rajeev Kumar
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