For sending the type, you dont have to denote it explicitly. Use templates.
template<typename T> void func (T *a) {
// business logic
}
I dont think you can pass operators directly.
For arithmetic operators, you could use something like this : [refer some
site for exact syntax]
template<typename T1, typename T2> void functioname ( T1 *argument, T2
operation) {
T1 result = operation(argument[1] , argument[2]);
}
main() {
int a[]={1,2,3,4,5};
functioname(a, std::multiplier<int>());
}
Karthik R,
R&D Engineer,
Tejas Networks.
On Mon, Sep 5, 2011 at 11:52 AM, punnu <punnu.gino...@gmail.com> wrote:
> I have to pass a general array in a function whose type will also be
> passed and also a function pointer for ">" or "<".
> e.g.
>
> void function(type , type array, "pointer for > or <")
>
> how will you write it in C?
>
> Thanxx in Advance
>
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