@Dave and Gene

sorry , i mean ur solutions are brilliant ,but i did not get those kind of
ideas till now..

On 13 September 2011 12:31, kumar raja <rajkumar.cs...@gmail.com> wrote:

> @Dave and Gene
>
> I am totally awkward at ur solutions ...How did u develop these solutions??
> . Can u please quote some material/book on this topic..
>
>
> On 13 September 2011 12:18, Sandy <sandy.wad...@gmail.com> wrote:
>
>> @Ankit.
>>
>> n=0000 1101
>>
>> i=2 j=3
>>
>> x = (2^j + 2^i) = 0000 1100
>> x^n = 0000 0001
>>
>> Answer should be 0000 1101.
>>
>> On Wed, Sep 14, 2011 at 12:39 AM, Ankit Agarwal 
>> <ankuagarw...@gmail.com>wrote:
>>
>>> let x = 2^j + 2 ^i
>>> new number after swapping the digits is x XOR n
>>>
>>> eg n = 0000 1101
>>> j = 6 i = 2
>>> x = 0100 0100
>>>  new number = x XOR n = 0100 1001
>>>
>>>
>>> --
>>> Ankit Agarwal
>>> Computer Science & Engg.
>>> Integrated Dual Degree, V yr
>>> Department of Electronics & Computer Engineering
>>> Indian Institute of Technology Roorkee
>>> Ph. no. +91-9580098805
>>>
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>>
>>
>>
>> --
>>
>> *Sandeep Kumar,*
>>  ( Mobile +91-9866507368
>>
>> *“I believe in smart work, Believe Me”*
>>
>>
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>
>
>
> --
> Regards
> Kumar Raja
> M.Tech(SIT)
> IIT Kharagpur,
> 10it60...@iitkgp.ac.in
> 7797137043.
> 09491690115.
>
>


-- 
Regards
Kumar Raja
M.Tech(SIT)
IIT Kharagpur,
10it60...@iitkgp.ac.in
7797137043.
09491690115.

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