output is -4 -1
int a:1 signifies that only 1 bit will be stored for a and since we have
only 1 bit so it will serve as sign bit and we get obj.a as -1
similarly for int b:3, 3 bits will be used to store b. 12 is 1100. we save
only 3 bits i.e. 100 where msb signifies the sign i.e. no. is negative. But
I am not able to represent the value -4 in 3 bits. Can anyone elaborate?
I think 00 is getting converted to 2's complement which is 100 = 4 and we
have negative sign bit set. So ans is -4. Correct me if I am wrong.
On Wed, Sep 21, 2011 at 10:22 PM, kartik sachan <kartik.sac...@gmail.com>wrote:
>
> int main(){
> struct {
> int a:1;
> int b:3;
> }obj;
> obj.b=12;
> obj.a=7;
> printf
> <http://www.opengroup.org/onlinepubs/009695399/functions/printf.html>("%d
> %d",obj.b,obj.a);return 0;}
>
>
>
> can anybody explain the output
> plzz also show how no's are stored
>
>
> --
>
> *WITH REGARDS,*
> *
> *
> *KARTIK SACHAN*
>
> *B.TECH 3rd YEAR*
> *COMPUTER SCIENCE AND ENGINEERING*
> *NIT ALLAHABAD*
>
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Regards
Ravi Maggon
B.E. CSE, Final Year
Thapar University
www.algorithmguru.com
"*Failure is the opportunity to begin again more intelligently"*
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