use a max heap of size k,

On Tue, Nov 22, 2011 at 11:38 PM, Aamir Khan <ak4u2...@gmail.com> wrote:

>
> On Tue, Nov 22, 2011 at 8:43 PM, Dave <dave_and_da...@juno.com> wrote:
>
>> @Ganesha: You could use a max-heap of size k in time O(n log k), which
>> is less than O(n log n) if k < O(n).
>
>
> We can always ensure that k <= n/2.
>
> If k >= n/2 then the problem can be stated as, find m points farthest from
> the given point by creating min-heap of size m. The elements which were
> present in input but not in heap will be the points nearest to the given
> point, where m = n-k.
>
>
>
>
>> Dave
>>
>> On Nov 22, 8:56 am, ganesha <suresh.iyenga...@gmail.com> wrote:
>> > Given a set of points in 2D space, how to find the k closest points
>> > for a given point, in time better than nlgn.
>>
>>
>
> --
> Aamir Khan | 3rd Year  | Computer Science & Engineering | IIT Roorkee
>
>
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