@kunzmilan
Nice idea, how do you decide the row-size or column-size of the matrix?


On Thu, Nov 24, 2011 at 8:00 PM, kumar raja <rajkumar.cs...@gmail.com>wrote:

> @kunzmilan :
> Can u please maintain the clarity ??
> How did u find the M
>
> if the list is 4 2 8 9  5 1 9 how M looks like ?? please elaborate it...
>
>
> On 24 November 2011 06:15, kunzmize an <kunzmi...@atlas.cz> wrote:
>
>>
>>
>> On 24 lis, 09:09, kumar raja <rajkumar.cs...@gmail.com> wrote:
>> > @kunzmilan : i did not get  u, once explain with example...
>> >
>> > On 23 November 2011 23:47, kunzmilan <kunzmi...@atlas.cz> wrote:
>> Matrix M
>> 0 1 0
>> 0 1 0
>> 1 0 0
>> multiplied with M(T)
>> 0 0 1
>> 1 1 0
>> 0 0 0
>> gives
>> 1 0 0
>> 0 2 0
>> 0 0 0.
>> On its diagonal are numbers of repeated elements.
>> kunzmilan
>>
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > > On 24 lis, 07:02, kumar raja <rajkumar.cs...@gmail.com> wrote:
>> > > > In the given array all the elements occur single time except  one
>> element
>> > > > which occurs  2 times find it in O(n) time and O(1) space.
>> >
>> > > > e.g.  2 3 4 9 3 7
>> >
>> > > > output :3
>> >
>> > > > If such a solution exist can we extend the logic to find "All the
>> > > repeated
>> > > > elements in an array in O(n) time and O(1) space"
>> >
>> > > > --
>> > > > Regards
>> > > > Kumar Raja
>> > > > M.Tech(SIT)
>> > > > IIT Kharagpur,
>> > > > 10it60...@iitkgp.ac.in
>> > > > Write the list in the form of a matrix M, e.g.
>> > > > 0 1 0 0...
>> > > > 0 0 1 0...
>> > > > 0 0 0 1...
>> > > > ......etc.,
>> > > > and its quadratic form M(T)M shows, how many times each element
>> repeats.
>> > > kunzmilan
>> >
>> > > --
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>> >
>> > --
>> > Regards
>> > Kumar Raja
>> > M.Tech(SIT)
>> > IIT Kharagpur,
>> > 10it60...@iitkgp.ac.in
>>
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>
>
> --
> Regards
> Kumar Raja
> M.Tech(SIT)
> IIT Kharagpur,
> 10it60...@iitkgp.ac.in
>
>
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-- 
Anup Ghatage

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