@sourabh can you explain me how it will work for this example???? a[]={2,7,3,4,5,8,10}
On Dec 7, 12:17 am, sourabh singh <singhsourab...@gmail.com> wrote: > @ sourabh :-) yep, got your point... it wont work for all cases. > but > if we set initial max to a negative value . say max possible 64 bit > -ve number.then ? > point is though the code has limitations it will work fine mostly. > > On 12/5/11, sourabh <sourabhd2...@gmail.com> wrote: > > > > > > > > > @sourabh singh.. > > > Hey u don't need an example... I see a check "sum > max" in ur code to > > calculate the max value, ryt ? Now ur initial value of max is set to > > 1. That means ur always assuming that the value whose closest is to be > > found is >= 1 , which is incorrect. What do you think ? > > > On Dec 6, 12:24 am, sourabh singh <singhsourab...@gmail.com> wrote: > >> @ sourabh tried some cases its working on -ve as well. pls post some > >> case in which it might not work. > > >> On 12/5/11, sourabh <sourabhd2...@gmail.com> wrote: > > >> > @sourabh.. > > >> > I don't think it will work for all the cases.. did u consider negative > >> > integers as well... what i can understand from the above code is that > >> > u have taken 2 pointers of which one points to the beginning of the > >> > subarray and other one at the end of the subarray and u r shifting the > >> > pointers based on the closest value.. this app is fine for non- > >> > negative integers but will fail when the given input contains both neg > >> > and pos integers... > > >> > On Dec 5, 4:25 pm, sourabh singh <singhsourab...@gmail.com> wrote: > >> >> @ mohit my first post on here. this solution got ac in spoj > > >> >> main() > >> >> { > >> >> unsigned int n,m,sum,max,i,j; > >> >> sum=0;max=1; > >> >> n=in.ReadNextUInt(); > >> >> m=in.ReadNextUInt(); > >> >> unsigned int *a = new unsigned int[n]; > >> >> unsigned int *p = a; > >> >> for (i=0; i < n; i++) > >> >> *(p++) = in.ReadNextUInt(); > >> >> i=0; > >> >> j=0; > >> >> while(j<n) > >> >> { > >> >> sum+=a[j++]; > >> >> while(sum>m) > >> >> { > >> >> sum-=a[i++]; > >> >> } > >> >> if(sum>max) > >> >> max=sum; > >> >> } > >> >> out.WriteUInt(max,'\n'); > > >> >> out.Flush(); > >> >> return 0; > > >> >> } > > >> >> On 11/28/11, Mohit kumar lal <kumarmohit...@gmail.com> wrote: > > >> >> > Given a array of positive integers ,You have to find the largest sum > >> >> > possible from consecutive sub-array but sum should be less than or > >> >> > equal > >> >> > to > >> >> > K and also find that sub-array. Ex- array={2,1,3,4,5} k=12, > >> >> > ans->12, sub-array={3,4,5} > > >> >> > Firstly i tried with brute-force and then i also tried to solve it by > >> >> > DP > >> >> > but complexity were same ( O(n^2)) ....so plz try to provide a > >> >> > solution > >> >> > for > >> >> > O(nlgn) or O(n). > > >> >> > -- > >> >> > Mohit kumar lal > > >> >> > IIIT ALLAHABAD > > >> >> > -- > >> >> > You received this message because you are subscribed to the Google > >> >> > Groups > >> >> > "Algorithm Geeks" group. > >> >> > To post to this group, send email to algogeeks@googlegroups.com. > >> >> > To unsubscribe from this group, send email to > >> >> > algogeeks+unsubscr...@googlegroups.com. > >> >> > For more options, visit this group at > >> >> >http://groups.google.com/group/algogeeks?hl=en. > > >> > -- > >> > You received this message because you are subscribed to the Google > >> > Groups > >> > "Algorithm Geeks" group. > >> > To post to this group, send email to algogeeks@googlegroups.com. > >> > To unsubscribe from this group, send email to > >> > algogeeks+unsubscr...@googlegroups.com. > >> > For more options, visit this group at > >> >http://groups.google.com/group/algogeeks?hl=en. > > > -- > > You received this message because you are subscribed to the Google Groups > > "Algorithm Geeks" group. > > To post to this group, send email to algogeeks@googlegroups.com. > > To unsubscribe from this group, send email to > > algogeeks+unsubscr...@googlegroups.com. > > For more options, visit this group at > >http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.