Dudes, The 1st part is clear and easy also, since it will do the static
linking and will call the base class destructor .
But for my surprize, it calls the destructor(base class) and soon after
that it crashes out.
I wanted to know the reason as why it *crashes out*.
On Wed, Dec 7, 2011 at 5:16 PM, himanshu kansal <himanshukansal...@gmail.com
> wrote:
> ya...sorry only baseclass des would be called....
>
>
> On Wed, Dec 7, 2011 at 4:00 PM, Amit Basak <abas...@gmail.com> wrote:
>
>> For the main question, the base class destructor will be called and the
>> output of the program will be: "baseClass Des called".
>>
>> This is because, when delete bPtr; is called, the base class destructor
>> will be called as bPtr is of type baseClass.
>> And since baseClass destructor is not decalred as virtual, so the type of
>> the object that bPtr points to does not come into picture.
>> In other words, the base part of memory held by derivedClass2 object
>> will only be destructed here.
>>
>> @Prem Krishna Chettri's question: In this case also only the baseClass's
>> destructor will be called and hence we will have two lines output as
>> "baseClass Des called"
>> "baseClass Des called"
>>
>> This is why it is always advisable to make the destructor as virtual.
>>
>>
>> Amit
>>
>> On Wed, Dec 7, 2011 at 3:27 PM, Prem Krishna Chettri
>> <hprem...@gmail.com>wrote:
>>
>>> The Output would be only the base class object destructor would be
>>> called so output :-
>>>
>>> derivedClass2 Des called
>>>
>>> Now why ..
>>>
>>> It is no more than just a base parent concept here, so base pointer
>>> capable if holding its derived object address get's derived object as new
>>> derivedClass2() creates only derived object. However, by deleting that
>>> pointer would results in destructing of this object which is the object of
>>> the derived class type "derivedClass2".
>>>
>>>
>>> Well, I Guess what would be more interesting if you have a main
>>> something like this :-
>>>
>>> int main() {
>>>
>>> baseClass *aPtr = new derivedClass1();
>>>
>>> baseClass *bPtr = new derivedClass2();
>>> delete aPtr;
>>> delete bPtr;
>>> }
>>>
>>>
>>> On Wed, Dec 7, 2011 at 2:51 PM, deepak kumar
>>> <deepak.kuma...@gmail.com>wrote:
>>>
>>>> Hi All,
>>>> I am sharing with you all a problem . The problem is as follow
>>>>
>>>>
>>>> class baseClass {
>>>> public :
>>>> ~baseClass() { cout<< "baseClass Des called"<< endl; }
>>>> };
>>>>
>>>> /*Derived class*/
>>>>
>>>> class derivedClass1 : public baseClass {
>>>> public:
>>>> *virtual *~derivedClass1() {cout <<"derivedClass1 Des called"<<
>>>> endl;}
>>>> };
>>>>
>>>> /*Derived class*/
>>>>
>>>> class derivedClass2 : public baseClass {
>>>> public:
>>>> ~derivedClass2() {cout <<"derivedClass2 Des called"<< endl;}
>>>> };
>>>>
>>>>
>>>> int main() {
>>>>
>>>> baseClass *bPtr = new derivedClass2();
>>>> delete bPtr;
>>>> }
>>>>
>>>>
>>>> Can anyone tell me what will be the output and why ?
>>>> Note: the virtual destructor in derivedClass1.
>>>>
>>>>
>>>> --
>>>> Thanks and Regards
>>>> Deepak Kumar
>>>>
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>>>
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>>
>>
>>
>>
>>
>>
>>
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>
>
>
> --
>
> Regards
> Himanshu Kansal
> Msc Comp. sc.
> (University of Delhi)
>
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Thanks and Regards
Deepak Kumar
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