I tried the problem and written the code for it . it is in java. it is
printing all the possible numbers
I  am treating the differences ans an array of integers.

here is the code

public class Main {


    public static void main(String[] args)
    {
       int digit[]={3,2,5,1};// array of absolute differences

            int digit[]={3,2,5,1};
           for(int num=1;num<=9;num++) // call with all possible initial
numbers
           findNumber(digit,4,num,0,num);
    }

    public static void findNumber(int digit[],int n,int num,int i,int
oldDigit)
    {
        if(i==n)
        {
            System.out.print(num+"  ");
            return;
        }

        {
            int o=digit[i]+oldDigit;
            if(o<10)
                findNumber(digit,n,10*num+o,i+1,o);
            o=oldDigit-digit[i];
            if(o>0)
                findNumber(digit,n,10*num+o,i+1,o);

        }
    }

}

and here is the output

14612  14278  14276  25723  25721  25389  25387  36834  36832  36498  47945
 47943  41389  41387  58612  52498  69723  69721  63167  63165  74612
 74278  74276  85723  85721  85389  85387  96834  96832  96498
BUILD SUCCESSFUL (total time: 0 seconds)







On Tue, Dec 13, 2011 at 11:11 PM, Dave <dave_and_da...@juno.com> wrote:

> @Amir: Presumably, since these are digits in a number, they are
> bounded on the bottom by 0 and on the top by radix-1. So in decimal,
> if a digit is 7 and the absolute difference between it and the next
> digit is 3, there is only one possibility for the next digit, 7-3 = 4,
> since 7+3 is too large. So only some subset of the 2^(n-1)
> combinations of addition and subtraction may be possible.
>
> Dave
>
> On Dec 13, 4:15 am, Amir hossein Shahriari
> <amir.hossein.shahri...@gmail.com> wrote:
> > actually there are infinite number of sequences that match it
> > for example if the absolute differences are 3 2 5 1
> > one possible sequence is 6 3 5 0 1 one other is 7 4 6 1 2 or 8 5 7 2 3
> > and you can add any integer value to all elements and the result will
> still
> > be valid
> > actually you can start with any number and and then the second number
> will
> > be equal to the first number that you chose plus/minus the first absolute
> > difference and so on
> >
> > so if we are given the first element of the sequence there are 2^(n-1)
> ways
> > to find a valid sequence because for each absolute difference we can
> either
> > add the absolute difference to the last sequence element or subtract the
> > absolute difference from it
> >
> >
> >
> > On Mon, Dec 12, 2011 at 9:01 PM, KAY <amulya.manches...@gmail.com>
> wrote:
> > > If for a number n digits long, the absolute difference between
> > > adjacent digits is given, how to find out the number of different
> > > numbers with these absolute differences ?
> >
> > > for eg,
> > > if n=5
> > > and the absolute differences are
> > > 3 2 5 1
> > > then 1 possible number is
> > > 6 3 5 0 1    (because |6-3|=3,|3-5|=2 and so on...)
> >
> > > How many such numbers will be there?
> >
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 Regards*
*"The Coder"*

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more successfully u play"*

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