@Atul : got it. thanx :)
*
Sanjay Kumar
B.Tech Final Year
Department of Computer Engineering
National Institute of Technology Kurukshetra
Kurukshetra - 136119
Haryana, India
Contact: +91-8053566286
*



On Sun, Jan 8, 2012 at 3:27 AM, atul anand <atul.87fri...@gmail.com> wrote:

> @Sanjay: suppose Max_INT range is 300
>
> now suppose
>
> end=300 and start =2
>
> now using (start+end)/2 i.e *302*/2 but 302 goes out of range for and
> interger type as assumed...
>
> but if we use  start + (end-start)/2 THEN  2 + (300-2)/2  , i.e 2+ *298*/2
> here 298 < 300 hence it within int_Max range which was assumed 300..
>
>
>
> On Sun, Jan 8, 2012 at 4:41 PM, Sanjay Rajpal <sanjay.raj...@live.in>wrote:
>
>> actually book pages are images.
>>
>> My question is why second statement may result in overflow ?
>> *
>>
>> Sanjay Kumar
>> B.Tech Final Year
>> Department of Computer Engineering
>> National Institute of Technology Kurukshetra
>> Kurukshetra - 136119
>> Haryana, India
>> Contact: +91-8053566286, +91-9729683720
>> *
>>
>>
>>
>> On Sun, Jan 8, 2012 at 3:07 AM, saurabh singh <saurab...@gmail.com>wrote:
>>
>>>  not clear what you are trying to ask...can you quote exactly from the
>>> book?
>>> Saurabh Singh
>>> B.Tech (Computer Science)
>>> MNNIT
>>> blog:geekinessthecoolway.blogspot.com
>>>
>>>
>>>
>>> On Sun, Jan 8, 2012 at 4:34 PM, Sanjay Rajpal <srn...@gmail.com> wrote:
>>>
>>>> In binary search,
>>>>
>>>> mid = start + (end-start)/2 is used to avoid overflow, as said by a
>>>> book.
>>>>
>>>> why can't we use mid = (start + end)/2, it says this statement may
>>>> result in overflow ?
>>>> *
>>>> Sanjay Kumar
>>>> B.Tech Final Year
>>>> Department of Computer Engineering
>>>> National Institute of Technology Kurukshetra
>>>> Kurukshetra - 136119
>>>> Haryana, India
>>>> Contact: +91-8053566286
>>>> *
>>>>
>>>>  --
>>>> You received this message because you are subscribed to the Google
>>>> Groups "Algorithm Geeks" group.
>>>> To post to this group, send email to algogeeks@googlegroups.com.
>>>> To unsubscribe from this group, send email to
>>>> algogeeks+unsubscr...@googlegroups.com.
>>>> For more options, visit this group at
>>>> http://groups.google.com/group/algogeeks?hl=en.
>>>>
>>>
>>>  --
>>> You received this message because you are subscribed to the Google
>>> Groups "Algorithm Geeks" group.
>>> To post to this group, send email to algogeeks@googlegroups.com.
>>> To unsubscribe from this group, send email to
>>> algogeeks+unsubscr...@googlegroups.com.
>>> For more options, visit this group at
>>> http://groups.google.com/group/algogeeks?hl=en.
>>>
>>
>>  --
>> You received this message because you are subscribed to the Google Groups
>> "Algorithm Geeks" group.
>> To post to this group, send email to algogeeks@googlegroups.com.
>> To unsubscribe from this group, send email to
>> algogeeks+unsubscr...@googlegroups.com.
>> For more options, visit this group at
>> http://groups.google.com/group/algogeeks?hl=en.
>>
>
>  --
> You received this message because you are subscribed to the Google Groups
> "Algorithm Geeks" group.
> To post to this group, send email to algogeeks@googlegroups.com.
> To unsubscribe from this group, send email to
> algogeeks+unsubscr...@googlegroups.com.
> For more options, visit this group at
> http://groups.google.com/group/algogeeks?hl=en.
>

-- 
You received this message because you are subscribed to the Google Groups 
"Algorithm Geeks" group.
To post to this group, send email to algogeeks@googlegroups.com.
To unsubscribe from this group, send email to 
algogeeks+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/algogeeks?hl=en.

Reply via email to