http://www.geeksforgeeks.org/archives/8405

^ Similar question.

On Sun, Mar 25, 2012 at 5:19 PM, atul anand <atul.87fri...@gmail.com> wrote:

> wont work for all cases...ignore
> i will post the algo....once i fix it
> On 25 Mar 2012 17:06, "Amol Sharma" <amolsharm...@gmail.com> wrote:
>
>> @atul : it would be better for all to understand if you write the algo
>> instead of writing the code..
>> --
>>
>>
>> Amol Sharma
>> Third Year Student
>> Computer Science and Engineering
>> MNNIT Allahabad
>>  <http://gplus.to/amolsharma99> 
>> <http://twitter.com/amolsharma99><http://in.linkedin.com/pub/amol-sharma/21/79b/507><http://www.simplyamol.blogspot.com/>
>>
>>
>>
>>
>>
>>
>> On Sun, Mar 25, 2012 at 4:51 PM, atul anand <atul.87fri...@gmail.com>wrote:
>>
>>> @shady : yes i guess this is what question says:-
>>> so acc to this below algo work , i didnt execute it but i guess it will
>>> work
>>>
>>> void nextSmaller(int arr[],int n)
>>> {
>>> s1 s;
>>> int i,next,ele;
>>>
>>> s.top=-1;
>>> push(&s,0);
>>>
>>> for(i=1;i<n;i++)
>>> {
>>> next=arr[i];
>>>  if(isEmpty(&s))
>>> {
>>>       ele=pop(&s);
>>>       while(arr[ele] > next)
>>>       {
>>>  swap(arr,ele,i);
>>>                   next=arr[ele];
>>> if(isEmpty(&s)==0)
>>> {
>>> break;
>>>  }
>>>   ele=pop(&s);
>>>       }
>>>       if(ele > next)
>>>       {
>>> push(&s,ele);
>>>       }
>>>
>>> }
>>>
>>> push(&s,i);
>>>  }
>>>
>>> }
>>>
>>>
>>> On Sun, Mar 25, 2012 at 4:36 PM, shady <sinv...@gmail.com> wrote:
>>>
>>>> @gene
>>>> i think for  3 4 2 you need to start from left most element, and then
>>>> make substitutions one by one.
>>>> so it will be
>>>> 3 4 2
>>>> 2 4 3
>>>> 2 3 4
>>>>
>>>>
>>>> @all i googled a bit, and found that O(n) solution is possible for it,
>>>> any idea ?
>>>>
>>>> On Sun, Mar 25, 2012 at 1:59 PM, Kartik Sachan <kartik.sac...@gmail.com
>>>> > wrote:
>>>>
>>>>> +1 @saurabh...:P
>>>>>
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