Hi all,

I am new to this group.

My last post was deleted i do not know the reason behind it.

I will explain my logic here:-

as the range is 1 to n^2 we have a input array like input[n^2].
We can take a auxillary array of size n^2 like aux[n^2].
Scan the input array.
For each input input[i] increment by one corresponding aux[input[i]].
After this just iterate through the aux array printing the index aux[i]
times.

This way we can sort it in O(n) time.

On Sat, May 5, 2012 at 2:02 PM, saurabh singh <saurab...@gmail.com> wrote:

> After giving some thought,I think even radix sort may not be sufficient.
> Complexity of radix sort is O(k*n) where k is the number of buckets
> required to sort the given range.
> The number of buckets is proportional to the number of bits required to
> represent the *maximum number in the given range.*For our case the
> maximum number is O(n^2).Hence *the number of buckets required would be
> proportional to log(n^2) in the worst case.*
> Hence the worst case complexity for the given constraints using radix sort
> would be *O(n*(log n^2)) = O(n*logn).*
> This is no better than comparision sort.A slight optimization that we can
> make is to use a higher base which would reduce the number of buckets
> required but would add the cost of converting each number into  the higher
> base.
> Somehow I am getting convinced worst case O(n) algorithm may not be
> possible.Working on the mathematical proof.
>
> Saurabh Singh
> B.Tech (Computer Science)
> MNNIT
> blog:geekinessthecoolway.blogspot.com
>
>
>
> On Sat, May 5, 2012 at 8:37 AM, saurabh singh <saurab...@gmail.com> wrote:
>
>> @cegprakash They are n numbers lying in the range 1 to n^2.Not
>> necessarily sorted.
>> eg 3 4 1 2 5 8 (6 numbers satisfying the conditions given in the problem)
>> Saurabh Singh
>> B.Tech (Computer Science)
>> MNNIT
>> blog:geekinessthecoolway.blogspot.com
>>
>>
>>
>> On Sat, May 5, 2012 at 5:17 AM, Prakash D <cegprak...@gmail.com> wrote:
>>
>>> The range 1 to n^2 is already sorted
>>>
>>> On Sat, May 5, 2012 at 12:17 AM, Algobiz <deepak.arulkan...@gmail.com>
>>> wrote:
>>> > How to sort n numbers in the range of 1 to n^2 in O(n).. Any ideas?
>>> >
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-- 
*Thanks,
Jeevitesh Shekhar Singh.*

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