Geeks just look at this...correct me if i am wrong...!!
int main()
{
char s[] = "how are you friends";
int i=0;
while(s[i] != '\0')
{
if(s[i] == ' ' && s[i+1]==' ')
{ s[i+1] = '\b'; i++; }
else if(s[i]== ' ') s[i]='\a';
i++;
}
printf("%s\n", s);
}
On Wed, Aug 1, 2012 at 5:01 PM, atul anand <atul.87fri...@gmail.com> wrote:
> j=0;
> for i to len
> if(str[i] != ' ' )
> {
> str[j]=str[i];
> j++;
> }
> end
> str[j]='\0';
>
> On Wed, Aug 1, 2012 at 10:08 AM, Sambhavna Singh
> <coolsambha...@gmail.com>wrote:
>
>> Please have a look at this :
>> http://www.careercup.com/question?id=14433699&utm_source=feedburner&utm_medium=email&utm_campaign=Feed%3A+Careercup+%28CareerCup%29
>>
>> What does inplace shifting imply here? Cant i keep 2 pointers and
>> overwrite a non space character onto a space character and advance both
>> pointers till one again hits a space character and other a non-space
>> character? Does that violate the condition given in the question?
>>
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>
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Thanks & Regards,
* Atul Kumar Pandey*
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