Sorry, about that. Read it as: Yes a hex digit is represented by 4 bits but 1 Byte is being read using a char pointer* and you're printing the values in those Bytes.
On 21 October 2012 01:03, Saurabh Kumar <srbh.ku...@gmail.com> wrote: > Sorry, I don't understand your question. *%.2x *is only a precision > specifier still. > (%.2x was used for neat formatting only, because you are printing the > values only 1 Byte long and a Byte can occupy at max 2digits in hex) > > >>>>hex representated by 4 bits. > Yes hex is represented by 4 bits i.e. 1 Byte and that's what you are > reading with a char pointer*, 1 Byte each time and printing the values in > those Bytes. > > >>>>total we have to represent 32 bits and 8 bits in each....plz xplain > Each output represents 32bits only. 1 Byte each (in total 4Bytes) > > It's showing you the memory layout. You stored *i = 1; *and when probed > it using a char pointer. you found following four bytes written: *01 00 > 00 00* > It shows that on your machine: > 1. int is 4bytes long. (4x1Byte) > 2. First byte stores the least significant value, hence you are working on > a Little endian machine. > > similarly, for pointer: > char pointer reads 1 Byte at a time. It read 4Bytes in total i.e. 32 bits. > Hence, you are working on a 32 bit machine. (as pointer has value: *44 ff > 28 00, *address of i)*.* > * > * > * > * > PS: This is an algorithm group, please refrain from asking such language > specific questions. > > On 21 October 2012 00:19, rahul sharma <rahul23111...@gmail.com> wrote: > >> Actually i have taken form http://www.geeksforgeeks.org/archives/730 >> Please explain me o/p...as hex representated by 4 bits....then how cum is >> following o/p >> 00 00 80 3f >> 01 00 00 00 >> 44 ff 28 00 >> 01 00 00 00 >> >> total we have to represent 32 bits and 8 bits in each....plz xplain >> >> On Sun, Oct 21, 2012 at 12:05 AM, rahul sharma >> <rahul23111...@gmail.com>wrote: >> >>> void show_bytes(byte_pointer start, int len) >>> { >>> int i; >>> for (i = 0; i < len; i++) >>> printf(" %.2x", start[i]); >>> printf("\n"); >>> } >>> >>> >>> >>> byte_pointr is unsigned char *...typedef unsigned char * byte_pointer.... >>> plz tell me use of %.2x i knowx is for hexa........does it mean print 8 >>> bites of address in 4 hexa of 2 bits???i cant get xactly plz explain >>> >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to algogeeks@googlegroups.com. >> To unsubscribe from this group, send email to >> algogeeks+unsubscr...@googlegroups.com. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
