as rahul said, pathLen is pass by value, so it is overwriting the old
values at index pathLen in path[]. path[] is pass by ref.

On Thu, Oct 25, 2012 at 3:04 AM, rahul sharma <rahul23111...@gmail.com>wrote:

> I think it is overwritng old values when child end..parent overwrite old
> value with new..m i ryt?
>
>
> On Thu, Oct 25, 2012 at 3:00 AM, rahul sharma <rahul23111...@gmail.com>wrote:
>
>> I wana ask that when we pass array by recursion then as we know formal
>> parameters are passed by value and array by base address/pointre..so in
>> following program path[] arra contain differnt data each recursive call and
>> when child function return their data is also deleted i.e when we are at
>> parent there is only data till parent.So we are having different values in
>> array in recursion tre..So does it passes by value in recursion.If No then
>> hw this is implemented??Silly doubt..Please comment....thnx in advance...  
>> Given
>> a binary tree, print out all of its root-to-leaf paths one per line.
>> void printPathsRecur(struct node* node, int path[], int pathLen)
>>  {
>>    if (node==NULL) return;
>>
>>   /* append this node to the path array */
>>    path[pathLen] = node->data;
>>    pathLen++;
>>
>>   /* it's a leaf, so print the path that led to here */
>>    if (node->left==NULL && node->right==NULL)
>>    {
>>      printArray(path, pathLen);
>>    }
>>    else
>>    {
>>    /* otherwise try both subtrees */
>>      printPathsRecur(node->left, path, pathLen);
>>      printPathsRecur(node->right, path, pathLen);
>>    }
>>  }
>>
>
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