As per o/p below: 00 00 80 3f 01 00 00 00 44 ff 28 00 01 00 00 00 first byte address is first row. second byte address is second row. third byte address third row and so on
but how first row containg 3 values...as 1byte=2hexdigits..si only two digits must be there. and u said 44 ff 28 00 is address of i..how???getting a lot confused..plz clearify..thnx in advance On Sun, Oct 21, 2012 at 1:10 AM, Saurabh Kumar <srbh.ku...@gmail.com> wrote: > Sorry, about that. > Read it as: > Yes a hex digit is represented by 4 bits but 1 Byte is being read using a > char pointer* and you're printing the values in those Bytes. > > > On 21 October 2012 01:03, Saurabh Kumar <srbh.ku...@gmail.com> wrote: > >> Sorry, I don't understand your question. *%.2x *is only a precision >> specifier still. >> (%.2x was used for neat formatting only, because you are printing the >> values only 1 Byte long and a Byte can occupy at max 2digits in hex) >> >> >>>>hex representated by 4 bits. >> Yes hex is represented by 4 bits i.e. 1 Byte and that's what you are >> reading with a char pointer*, 1 Byte each time and printing the values in >> those Bytes. >> >> >>>>total we have to represent 32 bits and 8 bits in each....plz xplain >> Each output represents 32bits only. 1 Byte each (in total 4Bytes) >> >> It's showing you the memory layout. You stored *i = 1; *and when probed >> it using a char pointer. you found following four bytes written: *01 00 >> 00 00* >> It shows that on your machine: >> 1. int is 4bytes long. (4x1Byte) >> 2. First byte stores the least significant value, hence you are working >> on a Little endian machine. >> >> similarly, for pointer: >> char pointer reads 1 Byte at a time. It read 4Bytes in total i.e. 32 >> bits. Hence, you are working on a 32 bit machine. (as pointer has value: >> *44 ff 28 00, *address of i)*.* >> * >> * >> * >> * >> PS: This is an algorithm group, please refrain from asking such language >> specific questions. >> >> On 21 October 2012 00:19, rahul sharma <rahul23111...@gmail.com> wrote: >> >>> Actually i have taken form http://www.geeksforgeeks.org/archives/730 >>> Please explain me o/p...as hex representated by 4 bits....then how cum >>> is following o/p >>> 00 00 80 3f >>> 01 00 00 00 >>> 44 ff 28 00 >>> 01 00 00 00 >>> >>> total we have to represent 32 bits and 8 bits in each....plz xplain >>> >>> On Sun, Oct 21, 2012 at 12:05 AM, rahul sharma >>> <rahul23111...@gmail.com>wrote: >>> >>>> void show_bytes(byte_pointer start, int len) >>>> { >>>> int i; >>>> for (i = 0; i < len; i++) >>>> printf(" %.2x", start[i]); >>>> printf("\n"); >>>> } >>>> >>>> >>>> >>>> byte_pointr is unsigned char *...typedef unsigned char * >>>> byte_pointer.... >>>> plz tell me use of %.2x i knowx is for hexa........does it mean print >>>> 8 bites of address in 4 hexa of 2 bits???i cant get xactly plz explain >>>> >>> >>> -- >>> You received this message because you are subscribed to the Google >>> Groups "Algorithm Geeks" group. >>> To post to this group, send email to algogeeks@googlegroups.com. >>> To unsubscribe from this group, send email to >>> algogeeks+unsubscr...@googlegroups.com. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >> >> > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to algogeeks@googlegroups.com. > To unsubscribe from this group, send email to > algogeeks+unsubscr...@googlegroups.com. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
