Since this is a small grid you can count it manually but in general problem
is to count no. of paths from bottom-left corner to top-right corner
(provided all the transition alphabets in the automata are distinct in
the respective dimensions e.g. here,  xyz in one  dimension and abc in
other)

You can view this problem as writing all permutations of strings of 3R's
and 3U's (for RIGHT movement and UP movement) RRRUUU which will take you to
the top right most corner.
All possible arrangements = (3+3)! / (3! * 3!)
In general: (m+n)! / (m! * n!) for a mxn grid.

On 27 October 2012 11:05, rahul sharma <rahul23111...@gmail.com> wrote:

> should i take it how many ways are there to reach from start to  the top
> right destination...x,y,z,a,b,c, are i/p state....xyzabc one string....abc
> xyz is another...if m ryt then is dere any formulla to calute or we have to
> do it manuallyyyy
>
>
> On Sat, Oct 27, 2012 at 11:02 AM, rahul sharma <rahul23111...@gmail.com>wrote:
>
>>
>> can u please elaborate...i am not able to understand the figure..plz
>> explain....it would be of great help
>>
>> On Sat, Oct 27, 2012 at 5:57 AM, payal gupta <gpt.pa...@gmail.com> wrote:
>>
>>> should be 6C3 or 20 perhaps.
>>>
>>> On Sat, Oct 27, 2012 at 3:29 AM, rahul sharma 
>>> <rahul23111...@gmail.com>wrote:
>>>
>>>> Finite state automata accpt string of length 6
>>>>
>>>> what is total number of strings in set..please find the attahcment
>>>>
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