writes: > Hello, > I have a question on iptables. On the arch wiki, the tutorial on a simple > stateful firewall includes the creation of the following rule.
> # iptables -A INPUT -p tcp --syn -m state --state NEW -j OPEN-TCP > Which, to my understanding, meant only pass new TCP streams with the syn flag > (the initialize connection or handshake part 1 of 3) to the user defined > chain. When I checked the output of iptables, I noticed the following rule. > # iptables -L INPUT --line-numbers -v > 7 OPEN-TCP tcp -- anywhere anywhere tcp > flags:FIN,SYN,RST,ACK/SYN state NEW > Why is iptables also using the FIN, RST and ACK/SYN flags? Did I not request > SYN only like I thought the tutorial said? > Read the man page of iptables. -- Ashish SHUKLA | GPG: F682 CDCC 39DC 0FEA E116 20B6 C746 CFA9 E74F A4B0 freebsd.org!ashish | http://people.freebsd.org/~ashish/ “He who hasn't hacked assembly language as a youth has no heart. He who does as an adult has no brain.” (John Moore)
