SOrry I forget interval of 1.5
2000000/8*1.5
Subject: RE: [OSL | CCIE_RS] Simple 3560 policing question
Date: Thu, 28 Jan 2010 15:02:30 -0600
From: [email protected]
To: [email protected]; [email protected]
But that would = 250000 bits or 31250 bytes; not 375000.
Derek Mills
Network Engineer
cell 314-575-8681 | Nextel dc 140*1*26466
[email protected] | www.thinkapplied.com
From: pra pa [mailto:[email protected]]
Sent: Thursday, January 28, 2010 2:58 PM
To: Mills, Derek; [email protected]
Subject: RE: [OSL | CCIE_RS] Simple 3560 policing question
2000000/8
Date: Thu, 28 Jan 2010 14:51:39 -0600
From: [email protected]
To: [email protected]
Subject: [OSL | CCIE_RS] Simple 3560 policing question
I'm certain I should know this but I can't get the math worked out.
Task 22.2 in Workbook one has you configure an aggregate policer. The DSG lists
the policing command as:
mls qos aggregate-policer Port1-2mPolicy 2000000 375000 exceed drop
My question is how is the burst rate calculated? I thought it was CIR/Tc.
Doesn't Tc=25ms on Fa interface?
Anheuser-Busch InBev Email Disclaimer www.ab-inbev.com
Hotmail: Free, trusted and rich email service. Get it now.
_________________________________________________________________
Hotmail: Trusted email with powerful SPAM protection.
http://clk.atdmt.com/GBL/go/196390707/direct/01/_______________________________________________
For more information regarding industry leading CCIE Lab training, please visit
www.ipexpert.com
