You are of course correct.
I answered quickly about to run out the door without thinking the
whole thing through and was quickly thinking about a ^ matching the
beginning of a literal string.
Which it does. Except as Matthew pointed out - when directly following
a open sqaure bracket with one/other character(s) inside - then it
matches anything except what is in the square brackets.
Frog - For some more fun reading:
http://www.cisco.com/en/US/docs/ios/12_2/termserv/configuration/guide/tcfaapre_ps1835_TSD_Products_Configuration_Guide_Chapter.html
http://en.wikipedia.org/wiki/Regular_expression
And if you are REALLY bored:
http://www.regular-expressions.info/
And in real life (not the lab unfortunately) - there is always
RegexBuddy: Learn, Create, Understand, Test, Use and Save Regular
Expression
GREAT for creating terribly complex regex patterns for programming
languages.
Cheers and thanks for correcting my error Matthew!
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Mark Snow
CCIE #14073 (Voice, Security)
Senior Technical Instructor - IPexpert, Inc.
Telephone: +1.810.326.1444
Fax: +1.309.413.4097
Mailto: [EMAIL PROTECTED]
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On Jun 4, 2008, at 9:59 PM, Matthew Bynum wrote:
The ^ imediately after the open bracket ( as in [^ ) means anything
EXCEPT whatever is inside the brackets. So in your example:
pattern#1 = destination-pattern 7[^4]...$
pattern#2 = destination-pattern 74...$
Pattern #1 would match 75111 but not 74111.
Pattern #2 would match 74111 but not 75111.
:)
On Wed, Jun 4, 2008 at 4:30 PM, FrogOnDSCP46EF
<[EMAIL PROTECTED]> wrote:
Hi group,
pattern#1 = destination-pattern 7[^4]...$
pattern#2 = destination-pattern 74...$
Can anyone tell me whats the difference between patter1 vs pattern 2?
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Smile, you'll save someone else's day!
Frog
--
Matthew Bynum
Senior Consultant
ProSys
